Question

Question #d280e

Answer 1

`1000m`

Explanation:

Distance traveled `s` in time `t`. Applicable kinematic equation is
`s=ut+1/2at^2`
where `a` is acceleration and `u` is initial velocity.

Car a
`s_a=0xx60+1/2(0.75)(60)^2`
`s_a=1350m`

Car b
`s_b=0xx60+1/2(0.25)(60)^2`
`s_a=450m`

Difference is `=1350-450=900m`
When cars started Car a was ahead of Car b by`=100m`
After `1min` Car a is ahead of Car b by`=900+100m=1000m`