How do you solve #0= ( x - 8) ^ { 2} - 49#?
1 Answer
Apr 26, 2017
Perform opposite operations to the
Explanation:
Basically, all we have to do is perform opposite operations to the
So first off, let's move the
#0=(x-8)^2-49#
#49=(x-8)^2#
Now, let's square root the
#7=x-8#
Now, we move the
#15=x#
We now know that
#0=(x-8)^2-49#
#0=(15-8)^2-49#
#0=(7)^2-49#
#0=49-49#
#0=0#
We get the same answer! Therefore, we can conclude that
Hope this helps :)