How do you solve #0= ( x - 8) ^ { 2} - 49#?

1 Answer
Apr 26, 2017

Perform opposite operations to the #0#. In this case, we get #x=15#.

Explanation:

Basically, all we have to do is perform opposite operations to the #0#. This will isolate the #x#.

So first off, let's move the #-49# to the other side of the equation.

#0=(x-8)^2-49#

#49=(x-8)^2#

Now, let's square root the #49#. We do this because we have to do the opposite operation of the other: squaring is opposite to square rooting.

#7=x-8#

Now, we move the #-8# to the other side.

#15=x#

We now know that #x=15#. We can double check our work by subbing in #x=15# in the original equation and solving to see if it equals #0#.

#0=(x-8)^2-49#

#0=(15-8)^2-49#

#0=(7)^2-49#

#0=49-49#

#0=0#

We get the same answer! Therefore, we can conclude that #x=15#.

Hope this helps :)