Question #5352c

1 Answer
Apr 26, 2017

#2#

Explanation:

Let the integer be #x#

The sum of its square, which is #x^2# added to #6# times the integer which is #6x# gives an answer of #16#

So the equation is,

#rarrx^2+6x=16#

Take #16# to the left side of the equation

#rarrx^2+6x-16=0#

Now, factor it

#rarr(x+8)(x-2)=0#

When we solve for this we get two equations

#color(brown)(rArrx+8=0#

#color(purple)(rArrx-2=0#

We get the solutions as #x=-8 # or #x=2#

As already metioned in the question, that #x# is a positive integer, the answer would be

#color(green)(rArr2#

Hope this helps..! :)