Question

How do you multiply `b^ { 83} c ^ { 0} d ^ { 3} \cdot b ^ { 6} c ^ { 7} d ^ { 87}`?

Answer 1

See the solution process below:

Explanation:

First, rewrite this expression as:

`(b^83b^6)(c^0c^7)(d^3d^87)`

Now, use this rule of exponents to multiply each of the terms:

`x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))`

`(b^color(red)(83) xx b^color(blue)(6))(c^color(red)(0) xx c^color(blue)(7))(d^color(red)(3) xx d^color(blue)(87)) = b^(color(red)(83) + color(blue)(6))c^(color(red)(0) + color(blue)(7))d^(color(red)(3) + color(blue)(87)) = b^89c^7d^90`