Question

How do you simplify `\frac { 38a ^ { 9} b ^ { - 6} c ^ { - 1} } { - 4a ^ { - 5} b ^ { - 8} c }`?

Answer 1

Remember `x^-a = 1/x^a` and `1/x^-a = x^a` and `x^a/x^b = x^(a-b)`

Explanation:

`-(38a^9b^-6c^-1)/(4a^-5b^-8c) = -(19a^14b^8)/(2b^6c^2) = -(19a^14b^2)/(2c^2)`