Question #90d68

1 Answer
iceman
Apr 28, 2017

#x=-7#

Explanation:

To solve it I am assuming that it is equal to zero:
#x^2 + 14x + 49=0#
Recall: #(a+b)^2=a^2+2ab+b^2# => perfect square, so in this case:
#(x+7)^2=0#
#x+7=0#
#x=-7#

Methode 2: Using the Quadratic Formula:
If: #ax^2+bx+c=0# => Quadratic Equation: then:
#x=(-b+-sqrt(b^2-4ac))/(2b)# => Quadratic Formula: in this case:
#a=1,b=14,c=49# => then:
#x=(-14+-sqrt((14)^2-4*1*49))/(2*1)#
#x=(-14+-sqrt(196-196))/2#
#x=-14/2#
#x=-7#

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