How do you solve #7u - 35< - 4( 2- 4u )#?

1 Answer
Apr 28, 2017

#u> -3#

Explanation:

First, we'd want to distribute the #-4# to the numbers within the parentheses.

#-4(2-4u) = #
#-4*2# and #-4*-4u= #
#-8+16u#

Now, we have #7u-35<-8+16u#.

We'd want to isolate the variable, by having it on only one side of the equation.

We'd subtract the #16u# to the left side, and add the #-35# to the right side.

#7u-16u<-8+35#

We'd then solve.
#-9u<27#

We'd then simplify the #u# down to it's simplest form, so divide both sides by #-9#.

Because we're dividing by a negative number, we need to flip the sign from a #<# to a #>#.

So, #u> -3#