How do you use the matrix method to solve the system of equations #5x+3y = 3# and #2x-6y=30#?

2 Answers
Apr 30, 2017

I got:
#x=3#
#y=-4#

Explanation:

We can try using Cramer's Method:

1) evaluate the determinant of the matrix #A# formed with the coefficients of the unknowns:
#|(5,3),(2,-6)|=(-30-6)=-36#

2) evaluate the determinant of the matrix #A_x# formed with the first column of independent terms and the other with the coefficients of the unknowns:
#|(3,3),(30,-6)|=(-18-90)=-108#
3) find #x# by dividing:
#A_x/A=-108/-36=3#

4) evaluate the determinant of the matrix #A_y# formed with the second column of independent terms and the other with the coefficients of the unknowns:
#|(5,3),(2,30)|=(150-6)=144#
5) find #x# by dividing:
#A_y/A=144/-36=-4#

Apr 30, 2017

#x=3#
#y=-4#

Explanation:

Look at the image

#x=A_1/A=(-108)/(-36)=3#
#y=A_2/A=(144)/(-36)=-4#