Question

Question #cf765

Answer 1

It will increase by a factor of 8.

Explanation:

Just think through it mathematically:

Go ahead and plug in a 2 in for both `[Cl_2]` and `[NO_2]`.

You should get just a 2 from the `[Cl_2]`, but you'll get a 4 from the `[NO_2]` (because `2^2`). Multiply these together, and you get a factor of 8.

So regardless of what the actual concentrations of `Cl_2` and `NO_2` are, if you double both concentrations, your reaction rate will increase by a factor of 8.

Hope that helps :)