What is the average value of a function #y=50x+5# on the interval #[3,9]#?
2 Answers
Apr 30, 2017
Explanation:
The average value of a function
#"average value"=1/(b-a)int_a^bf(x)dx#
So here, the average value is:
#1/(9-3)int_3^9(50x+5)dx#
#=5/6int_3^9(10x+1)dx#
Integrating term by term:
#=5/6[5x^2+x]_3^9#
#=5/6[(5(9)^2+9)-(5(3)^2+3)]#
#=5/6(414-48)#
#=305#
Apr 30, 2017
Explanation:
Use the average function