Question

How do you evaluate `z(x+1)` if w=6, x=0.4, y=1/2, z=-3?

Answer 1

See the solution process below:

Explanation:

To evaluate this expression substitute `color(red)(-3)` for `color(red)(z)` and `color(blue)(0.4)` for `color(blue)(x)`. The values for `w` and `y` are not used in the expression and are extraneous or not needed or necessary:

`color(red)(z)(color(blue)(x) + 1)` becomes:

`color(red)(-3)(color(blue)(0.4) + 1) => color(red)(-3) * 1.4 => -4.2`

Answer 2

`z(x+1)=color(green)(-4.2)`

Explanation:

Given
`color(white)("XXX")color(orange)w=color(orange)6`
`color(white)("XXX")color(red)x=color(red)(0.4)`
`color(white)("XXX")color(brown)y=color(brown)(1/2)`
`color(white)("XXX")color(blue)z=color(blue)(-3)`

Then
`color(white)("XXX")color(blue)z(color(red)x+1)`
`color(white)("XXXXXXX")=(color(blue)(-3))xx(color(red)(0.4)+1)`
`color(white)("XXXXXXX")=(color(blue)(-3))xx1.4`
`color(white)("XXXXXXX")=-4.2`