Question

Question #aa31d

Answer 1

The concentrations of `"HCl"` and of `"NaCl"` are each 0.08 mol/L.

Explanation:

When you mix the two solutions, the new volume for each component becomes

`"10 mL + 50 mL = 60 mL"`

You can use the dilution formula

`color(blue)(bar(ul(|color(white)(a/a)c_1V_1 = c_2V_2color(white)(a/a)|)))" "`

to calculate the new concentrations.

`c_2 = c_1 × V_1/V_2`

Concentration of `"HCl"`

`c_2 = "0.5 mol/L" × (10 color(red)(cancel(color(black)("mL"))))/(60 color(red)(cancel(color(black)("mL")))) = "0.08 mol/L"`

Concentration of `"NaCl"`

`c_2 = "0.1 mol/L" × (50 color(red)(cancel(color(black)("mL"))))/(60 color(red)(cancel(color(black)("mL")))) = "0.08 mol/L"`