Question

Question #f092d

Answer 1

`1/2lnx^2+c`

Explanation:

We can use substitution to cancel out the `x`
`u=lnx`
`du=1/xdx`
`dx=xdu`

`intu/x\cdotxdu`
`=intudu`
`=1/2u^2+c`
`=1/2lnx^2+c`