How do you solve #5c + 3( 0.05) = 4c + 7( 0.05)#?

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Answer 1 · 2017-05-03T01:00:28

See the solution process below:

First, expand the terms in parenthesis by multiplying the term within the parenthesis by the term outside the parenthesis:

#5c + 3(0.5) = 4c + 7(0.05)#

#5c + 0.15 = 4c + 0.35#

Now, subtract #color(red)(0.15)# and #color(blue)(4c)# from each side of the equation to solve for #x# while keeping the equation balanced:

#-color(blue)(4c) + 5c + 0.15 - color(red)(0.15) = -color(blue)(4c) + 4c + 0.35 - color(red)(0.15)#

#(-color(blue)(4) + 5)c + 0 = 0 + 0.2#

#1c = 0.2#

#c = 0.2#