Question

Question #c8498

Answer 1

First one is `-8(2t-5)(t-1)`
Second one is `-4.9(t-1)(t-4)`
Last one is `-4.9(t-40)(t-10)`

Explanation:

Factor a number out of the equation, but make sure that the values are whole numbers. That's why we cannot factor -16, it'll turn them into fractions.
`-8(2t^2-7t+5)`
After that, use the cross method to solve the expression in the bracket. I can't really do the crosses, so I'll just multiply across.
`2t*-1=-2`
`t*-5=-5t`
Add the results together to see if they equal `-7t`
`-5t+(-2t)=-7t`
Now, just bracket the expressions that are diagonal of each other, so if `2t and -5` are opposite of each other, bracket them together, hence, the cross method.

*NOTE - Normally, you would multiply diagonally and bracket the terms across, but I can't do that with these maths symbols, so I multiply across and bracket diagonally.
`-8(2t-5)(t-1)`

Apply the same method for the second and last one.
If you factor the `-4.9` out, you end up with whole numbers.
`-4.9(t^2-5t+4)`
`t*-4=-4t`
`t*-1=-t`
`-t+(-4t)=-5t`
`-4.9(t-1)(t-4)`

And the last one:
`-4.9(t^2-50t+400)`
(There are many ways to calculate 400 with multiplication, so just trial and error)
`t*-40=-40t`
`t*-10=-10t`
`-10+(-40t)=-50t`
`-4.9(t-40)(t-10)`