How do you solve #5c + 3= 4c + 7#?

1 Answer
smendyka
May 3, 2017

See the solution process below:

Explanation:

Subtract #color(red)(3)# and #color(blue)(4c)# from each side of the equation to solve for #c# while keeping the equation balanced:

#-color(blue)(4c) + 5c + 3 - color(red)(3) = -color(blue)(4c) + 4c + 7 - color(red)(3)#

#(-color(blue)(4) + 5)c + 0 = 0 + 4#

#1c =4#

#c = 4#

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