Question #40b17

1 Answer
Nityananda
May 3, 2017

#137/60#

Explanation:

Here #y^2 = x. so, y = x^(1/2) #

#z^3 =x. so, z = x^(1/3)#

#w^4 = x. so, w= x^(1/4)#

#u^5 = x. So, u = x^(1/5)#

Now, #logx ^(xyzwu) = logx^ [x^1.x^(1/2).x^(1/3).x^(1/4).x^(1/5)]#

#rArr logx ^[x^(1+1/2+1/3+1/4+1/5)]#

#rArr logx ^[x^(137/60)]#

#rArr 137/60 logx ^x#

#rArr137/60xx1 = 137/60#

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