How do you write the point slope form of the equation given (0,3) and (-1,-3)?

1 Answer
May 3, 2017

#y+3=6(x+1)#

Explanation:

#"the equation of a line in "color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#

#"where m represents the slope and " (x_1,y_1)" a point on the line"#

#"to calculate the slope use the "color(blue)"gradient formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#

#"where " (x_1,y_1),(x_2,y_2)" are 2 points on the line"#

#"the 2 points here are " (0,3)" and " (-1,-3)#

#"let " (x_1,y_1)=(0,3)" and " (x_2,y_2)=(-1,-3)#

#rArrm=(-3-3)/(-1-0)=(-6)/(-1)=6#

#"use either of the 2 given points for " (x_1,y_1)#

#"using " m=6" and " (x_1,y_1)=(-1,-3)#

#y-(-3)=6(x-(-1)larr"substitute in equation"#

#rArry+3=6(x+1)larrcolor(red)" in point-slope form"#