Given a #"molecular formula"# of #C_4H_8O_2#, what is the #"empirical formula"#?

1 Answer
anor277
May 4, 2017

Well the #"molecular formula"# is #C_4H_8O_2#.........

Explanation:

And the #"empirical formula"# is the simplest whole number ratio that defines constituent atoms in a species, and thus...................

#"empirical formula"# #=# #C_2H_4O#

The molecular formula is always a whole number multiple of the empirical formula, i.e............

#"molecular formula"=nxx{"empirical formula"}#.

To what does #n# equal here?

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