Question

Question #c64aa

Answer 1

The distance mentioned is less than the Fermi separation:

`d_F = 1.2 ( 4^(1/3) + (238 - 4)^(1/3)) approx 9.3 xx 10^(-15)`

So we go with Coulomb's Law with that qualification:

`mathbf F_alpha = - (k \ q_1 q_2)/r^2 mathbf e_r`

`implies F_alpha = (9 xx 10^9 \( 90 xx 2) (e^(-))^2)/(9 xx 10^(-15))^2 approx 577 " N"`