Question

1/2∫sec(x-π/3)dx?

Answer 1

`:.1/2intsec (x-pi/3)dx=1/2ln (sec (x-pi/3)+tan (x-pi/3))`

Explanation:

We know that
`intsecxdx= ln (secx+tanx)`
`:.1/2intsec (x-pi/3)dx=1/2ln (sec (x-pi/3)+tan (x-pi/3))`