Question

Question #0f2bd

Answer 1

`int_0^T (sin 2 pi t )/ T dt=1/(2piT)(1-cos (2piT))`

Explanation:

`int_0^T (sin 2 pi t )/ T dt=-1/(2pi)[(cos (2pit))/T]_0^T`
`=1/(2piT)(1-cos (2piT))`