A #66.5g# mass of a solute whose formula mass is #80.05gmol^-1# is used to prepare a solution of #315mL# volume. What is its molarity?

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Answer 1 · 2017-05-05T18:51:10

#"Molarity"~=2.7*mol*L^-1#

We want the quotient, #"moles of stuff (mol)"/"volume of solution (L)"# to give the #"molarity"#.

And thus #((66.5*g)/(80.05*g*mol^-1))/(315*mLxx10^-3*L*mL^-1)~=2.7*mol*L^-1#

A #66.5*g# mass of a solute whose formula mass is #80.05*g*mol^-1# is used to prepare a solution of #315*mL# volume. What is its molarity?