How do you subtract #\frac { 2x + 9} { x ^ { 2} - 7x + 12} - \frac { 2} { x - 3}#?

1 Answer
Karis Y. · [eden]
May 6, 2017

#(17)/(x-3)(x-4)#

Explanation:

Factorise #x^(2)-7x+12# to get #(x-4)(x-3)# so you have #(2x + 9)/((x-4)(x-3))- ( 2)/ ( x - 3)#
Now we have a common factor of #(x-3)# so the denominator and numerator of the second fraction has to multiply by #(x-4)# to have a same denominator.
So we have#(2x + 9)/((x-4)(x-3))- ( 2x-8)/ (( x - 3)(x-4))#
So we minus them to get #(17)/((x-3)(x-4))#

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