How to find the equation for a tangent to a circle with only one point?
How do you find the equation for a tangent to the circle #x^2+y^2-2x+10y-19=0# that passes through the point #(7,-2)# ?
How do you find the equation for a tangent to the circle
1 Answer
Please see the explanation.
Explanation:
Given
Verify that the point is on the circle:
Differentiate each term of the equation:
Move the terms that do not contain
Factor the left side:
Divide both sides by
The slope, m, of the tangent line at the point
Use the point slope form of the equation of line: