Question

How many grams of fluorine gas will exert a pressure of 1.54 atm in a 3.2-liter container at 40 °C?

Answer 1

You MUST know that elemental fluorine is the gaseous `F_2` molecule.

Explanation:

And in fact all the elemental gases, save for the Noble Gases, are bimolecular species. Is this true?

And we use the Ideal Gas Equation:

`PV=nRT="mass"/"molar mass"xxRT`

And thus `"mass"=(PVxx"molar mass")/(RT)`

And we plugs in the numbers:

`(1.54*atmxx3.2*Lxx38.0*g*mol^-1)/(0.0821*(L*atm)/(K*mol)xx313.1*K)=`

`7.29*g`.

Remember what I said with regard to the so-called molecularity of elemental gases. And fluorine gas, the most reactive substance on the Periodic Table, is not to be handled without special precautions.