How do you solve the system of equations #-4x - 8y = - 16# and #4x + 6y = 2#?

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Answer 1 · 2017-05-08T16:02:42

#y=7#
#x=-10#

Use the process of elimination. Add the two equations together. You should get:

#-2y=-14#

Solve for #y#:

#y=7#

Plug this in to one of the original equations. I'll plug it in to the second one:

#4x+6(7)=2#

Solve for #x#:

#4x=-40#

#x=-10#

Check by plugging into the other equation:

#-4(-10)-8(7)=-16#

#40-56=-16#

#-16=-16#