If the length of the equal two sides of a isosceles triangle is 20 cm and the angle between those two sides is 45 degrees, then what is the area of the triangle?

1 Answer

100 sqrt2 unit^2

Explanation:

Area of triangle =1/2 bc sin A where A = 45^@, b = c =20cm

Area of triangle = 1/2 *20*20*sin 45^@= 200*1/sqrt2=200/sqrt2 =100 sqrt2