What is the angular momentum of a rod with a mass of $4 kg$ and length of $6 m$ that is spinning around its center at $2 Hz$ ?

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Answer 1 · 2017-05-09T11:05:41

The angular momentum is $=150.8kgm^2s^-1$

The angular momentum is $L=Iomega$

and $omega$ is the angular velocity

The moment of inertia of a rod, rotating about the center is

$I=1/12*mL^2$

$=1/12*4*6^2= 12 kgm^2$

The angular velocity is

$omega=2*2pi$

$=(4pi) rads^(-1)$

The angular momentum is

$L=12*4pi=48pi=150.8kgm^2s^-1$

What is the angular momentum of a rod with a mass of 4 kg4 kg and length of 6 m6 m that is spinning around its center at 2 Hz2 Hz?