What is the angular momentum of a rod with a mass of #4 kg# and length of #6 m# that is spinning around its center at #2 Hz#?

Question

1201 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-09T11:05:41

The angular momentum is #=150.8kgm^2s^-1#

The angular momentum is #L=Iomega#

and #omega# is the angular velocity

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

#=1/12*4*6^2= 12 kgm^2#

The angular velocity is

#omega=2*2pi#

#=(4pi) rads^(-1)#

The angular momentum is

#L=12*4pi=48pi=150.8kgm^2s^-1#