How do you solve 2x36x2+x12x3?

1 Answer
May 9, 2017

Firstly set it = to 0 by taking away 2x3 from both sides.
This leaves us with:
2x36x2x+20
Then we can use the factor theorem to find one of our roots.
Start with f(x)=1
2(1)36(1)2(1)+2=3 Not a factor
Try 2
2(2)36(2)2(2)+2=8 Not a factor
Try 1
2(1)36(1)2(1)+2=7 Not a factor
Try 2
2(2)36(2)2(2)+2=36 Not a factor
Try 3
2(3)36(3)2(3)+2=1 Not a factor
Try 4
2(4)36(4)2(4)+2=30 Not a factor.

Very sorry I think I've done something wrong but I thought I'd send you my working a)because I find sometimes reading what someone else has done, even if wrong, helps to solve things and b)because I cant bring myself to get rid of that working.

It could be possible that you just need a factor higher than I'm using so feel free to try some, and if so you'll need to do some algebraic long division. Happy to show you this if you find a factor!