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Answer 1 · 2017-05-12T05:12:57

#122.5 m# from the top of the tower.

Using #v^2-u^2=at#, to find the velocity of the ball at the #5th# second of the fall.

Given #u=0#, #a=9.8# , #t=5#
we get #v= 49 m*s^-1#

Distance traveled by the stone is

#s=vt-(1/2)(g)(t^2)#

#s=49*5-(1/2)*10*5^2#

#s=122.5#

The stone is at distance of #122.5 m# from the top of the tower at the #5th# second.