How do you solve #v^ { 2} + 34v = 0#?

2 Answers
kumail
May 12, 2017

Factorization.

Explanation:

We can factor out a #v# from the given equation, doing this we get: #v * (v+34) = 0#

Now since two terms multiply to give us #0#, this means that one of them must be zero, so if the first term is #0# then #v = 0#, if the second term is #0#, then #v = -34#

So the solutions are #v = 0, v = -34#

John C.
May 12, 2017

#v= 0 or -34#

Explanation:

First off, identify that this is a quadratic equation, because the highest power of #v# is 2 (ie. #v^color(red)2#)

This means the solution has 2 answers.

Start by factoring out the #v#

#v (v+34)=0#

Now, this equation shows that either #v# or #(v+34)# is equal to zero.

#v = 0# or #v+34=0#

#v=-34#

Thus, #v = 0 or -34#

If you want to check your answers, substitute the #v# values back into the equation.

When #v=0,#

#0^2+34(0) = 0# (#v=0# is correct)

When #v=-34#,

#(-34)^2+34(-34)=0#
#1156-1156=0# (#v=-34 # is correct)

Thus, #0# and #-34# are the 2 solutions that were mentioned at the start.

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