If #cot theta = 2/3#, what is the value of #csc theta#?

1 Answer
Nityananda
May 13, 2017

#(sqrt13)/3#

Explanation:

We know,cot#theta = (base)/(height) = 2/3# [as per Pythagoras theory ].

Again as per Pythagoras theory,
#(hypotenuse)^2 = (base)^2+(height)^2#

#rArr (hypotenuse)^2 = 2^2+3^2#

#rArr hypotenuse = sqrt(13)#

Hence csc#theta = (hypotenuse)/(height) = (sqrt13)/3#

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