How do you solve $(6 z - 5) = 0$ $(6z - 5) = 0$ ?

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Answer 1 · 2017-05-13T14:13:17

See a solution process below:

First, remove the parenthesis, they are unnecessary:

$6 z - 5 = 0$ $6z - 5 = 0$

Next, add $5$ $color(red)(5)$ to each side of the equation to isolate the $z$ $z$ term while keeping the equation balanced:

$6 z - 5 + 5 = 0 + 5$ $6z - 5 + color(red)(5) = 0 + color(red)(5)$

$6 z - 0 = 5$ $6z - 0 = 5$

$6 z = 5$ $6z = 5$

Now, divide each side of the equation by $6$ $color(red)(6)$ to solve for $z$ $z$ while keeping the equation balanced:

$\frac{6 z}{6} = \frac{5}{6}$ $(6z)/color(red)(6) = 5/color(red)(6)$

$(color(red)(cancel(color(black)(6)))z)/cancel(color(red)(6)) = 5/6$

$z = 5/6$

How do you solve (6z - 5) = 0(6z−5)=0(6z - 5) = 0?