Why can't you just convert meters cubed to mL >> then >> convert mL to Liters? Giving: 0.019L (after Sig Figs)?? This references the video "Converting Metric Units of Volume."

2 Answers
May 13, 2017

#"1 cubic metre"# IS #1000*L# or #1000*dm^3#. I have not seen the video. And #18.8*m^3=18.8xx10^3*L...........#

Explanation:

A cubic metre is a HUGE volume. And #1*cm^3-=1*mL=10^-3*L#. These are all common units of volume in the laboratory. In Europe, we buy milk in litres, and in England, sometimes we buy milk in #"pints"#, #600*mL#.

#1*cm^3=(1xx10^-2*m)^3#. Why? Because the prefix #"centi"-=10^-2#. And thus............

#1*cm^3=(1xx10^-2*m)^3=1xx10^-6*m^3#.

Sometimes I remember that #1*m^3# (which is a HUGE volume!), is #1000*L#, and that there are #10^3*cm^3# in a #L#. An equivalent term for the #"litre"# is #"cubic decimeter"#, #dm^3#.

And thus #1000*L=10^3*Lxx10^-6*m^3=1xx10^-3*m^3#.

Equivalently #1*L=1*dm^3=(1xx10^-1*m)^3=10^-3*m^3#, as required.

It is worthwhile getting your head around these problems. If there is an issue you want further clarified ask away, and someone will help you.

May 13, 2017

There's no reason why you can't … if you know the conversion factors.

Explanation:

(By the way, the correct answer is 18 800 L.)

Do you know that the conversion is #"1 m"^3 = 10^6color(white)(l) "mL"#?

If so, you can write

#18.8 color(red)(cancel(color(black)("m"^3))) × (10^6 color(red)(cancel(color(black)("mL"))))/(1 color(red)(cancel(color(black)("m"^3)))) × "1 L"/(10^3 color(red)(cancel(color(black)("mL")))) = "18 800 L"#

However, that seems to me to be taking the long way around.

I would bet that more people remember the conversion, #"1 m"^3 = "1000 L"#.

They would write

#18.8 color(red)(cancel(color(black)("m"^3))) × "1000 L"/(1 color(red)(cancel(color(black)("m"^3)))) = "18 800 L"#

Both methods are equally valid.