Question

If I have 45 liters of helium in a balloon at 25 degress celcius and increase the tempurate to 55 degrees celcius what will the new volume be?

Answer 1

`50.L`

Explanation:

This is a problem involving the temperature-volume relationship of gases, which is represented by Charles's law:

`(V_1)/(T_1) = (V_2)/(T_2)`

Remember that `T` is the absolute temperature, so you must convert the temperature from Celcius to Kelvin:

`25 ^o C + 273 = 298K`
`55 ^o C + 273 = 328 K`

Now, rearrange the equation to solve for `V_2` (the new volume):

`V_2 = (V_1)(T_2)/(T_1)`

and plug in the known values:

`V_2 = 45 L(328 K)/(298 K) = 50.L`

(The decimal place is present to emphasize there are two significant figures, otherwise it's arbitrary whether you're using one or two.)