How do you combine #(3x \cdot 3y ) \div x y#?

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Answer 1 · 2017-05-14T04:27:30

See a solution process below:

First, rewrite this expression as:

#(3x * 3y) -: xy => (3x * 3y)/(xy)#

Next, factor the numerator as:

#((3 * 3)(x * y))/(xy) => (9 * xy)/(xy)#

Now, cancel common terms in the numerator and denominator:

#(9 * xy)/(xy) => (9 * color(red)(cancel(color(black)(xy))))/(color(red)(cancel(color(black)(xy)))) => 9#

As long as, or where: #xy != 0#

Or, where, #x != 0# or #y != 0#

Answer 2 · 2017-05-14T04:37:32

#color(blue)9#

#(3x*3y)-:xy#

#(3x xx 3y)-:xy#

#(9xy)/(xy)#

#color(blue)(=9#