How do you evaluate #4( 22- 11) + \frac { 2^ { 4} } { ( 10- 2) }#?

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Answer 1 · 2017-05-14T19:28:23

#46#

#4*(22-11)+2^4/(10-2)#

#22-11 = 11# and #10-2 = 8#

Therefore :

#4*(22-11)+2^4/(10-2)#

# = 4*11+2^4/8" "(and 8=2^3)#

#=> 2^4/8=2^4/2^3 = 2^(4-3)=2^1=2#

You have then

#4*11+2^4/8#

# = 44+2#

# = 46 #