Question

How do you multiply `-\frac { 2} { 5} x ^ { 2} y ^ { 3} \cdot \frac { 5} { 7} x ^ { 4} y ^ { 4}`?

Answer 1

`-2/5 x^2y^3 * 5/7 x^4y^4=-7/25x^6y^7`

Written in decimal form: `-7/25x^6y^7 = -0.29x^6y^7`

Explanation:

Given: `-2/5 x^2y^3 * 5/7 x^4y^4`

Performing multiplication within an expression, we can move the fractions together:

`(-2/5)(5/7) x^2y^3 * x^4y^4`

Now we can add exponents (by the exponent rule of multipication):

`(-2/cancel5)(cancel5/7)x^6y^7= -2/7x^6y^7= -0.29x^6y^7`