How do you solve h^ { 2} - 2h - 0= 3?

1 Answer
May 15, 2017

h = 3, -1

Explanation:

h^2 - 2h - 0 = 3

minus 3 to both sides,

h^2 - 2h - 3 = 0

use a quadratic formulae to solve where,
a = 1, b = -2 and c =-3

h = (-b +-sqrt (b^2 - 4ac))/(2a)

h = ( -(-2) +- sqrt((-2^2) - 4(1)(-3)))/(2(1))

h = ( 2 +- sqrt(4+ 12))/2

h = ( 2 +- sqrt(16))/2 = (2 +- 4)/2

h = (2 +4)/2, (2 - 4)/2

h = 3, -1