How do you solve #\frac { 1} { x+ 1} - 2= \frac { 2} { x - 2}#?

1 Answer
May 15, 2017

Make the equation equal to zero by subtracting the #2/(x-2)# on both sides, which makes the equation equal to 0.

#1/(x+1) -2 - 2/(x-2)# = 0

Then get rid of the denominators since fractions are hard to deal with in these types of problems.

So multiply the whole equation by #(x+1) and (x-2)#

#(x+1)(x-2) ((1/(x+1) -2 - 2/(x-2))) = 0#

Then simplify

#(x-2) - 2(x+1)(x-2) -2(x+1) = 0#

Then Expand

#x-2-2x^2 +2x +4 - 2x -2 =0#

Simplify

#-2x^2 +x =0#

Factor out a #-x#

#-x(2x-1) = 0#

Solve

#x= 0# and #x= 1/2#