What is the probability of rolling a fair die and not getting an outcome less than 2?

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What is the probability of rolling a fair die and not getting an outcome less than 2?

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Answer 1 · 2017-05-15T16:28:24

The probability is $\frac{5}{6}$ $5/6$ . See explanation.

Explanation:

First we can rephrase the task to avoid negation. The term "not to get an outcome less than 2" is the same as: "get 2 or more", so in other words the event is "you get 2 or more". Among all results $1, 2, 3, 4, 5$ $1,2,3,4,5$ and $6$ $6$ . only number $1$ $1$ does not fulfil the requirement, so other $5$ $5$ results fulfil it.

$A = {2, 3, 4, 5, 6}$ $A={2,3,4,5,6}$

$¯ ¯¯ ¯ ¯ ¯ ¯ A = 5$ $bar(bar(A))=5$

$bar(bar(Omega))=6$

so $P(A)=bar(bar(A))/bar(bar(Omega))=5/6$

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What is the probability of rolling a fair die and not getting an outcome less than 2?

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