How do you solve #4( 2x + 3) = 3( 3x + 2)#?

1 Answer
May 16, 2017

See a solution process below:

Explanation:

First, expand the terms in parenthesis on each side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(4)(2x + 3) = color(blue)(3)(3x + 2)#

#(color(red)(4) xx 2x) + (color(red)(4) xx 3) = (color(blue)(3) xx 3x) + (color(blue)(3) xx 2)#

#8x + 12 = 9x + 6#

Now, subtract #color(red)(8x)# and #color(blue)(6)# from each side of the equation to solve for #x# while keeping the equation balanced:

#-color(red)(8x) + 8x + 12 - color(blue)(6) = -color(red)(8x) + 9x + 6 - color(blue)(6)#

#0 + 6 = (-color(red)(8) + 9)x + 0#

#6 = 1x#

#6 = x#

#x = 6#