How do you solve #10( 2^ { x } ) + 9= 600#?

1 Answer
May 17, 2017

The goal is to get #x# isolated.

First subtract 9 from both sides to get rid of 9 from the left side

#10(2^x)=600-9#

Simplify

#10(2^x)=591#

Divide both sides by 10 to get #2^x# isolated

#2^x=59.1#

In order to get rid of an exponent one must #log# both sides of the equation

#xlog(2)=log(59.1)#

Then divide each side by #log(2)# to isolate #x#

#x=log(59.1)/log(2)#

Simplify

#x=5.885#