How do you combine like terms in #\frac { 3k } { 5k - 30} - \frac { 6} { k + 1}#?

1 Answer
May 17, 2017

What you are actually doing is expressing the difference between two rational functions as a single rational function.

We can say:

#(3k)/(5k - 30) - 6/(k + 1) => (3k)/(5(k - 6)) - 6/(k + 1)#

Hence, a common denominator is 5(k - 6)(k + 1)

i.e. #[3k(k + 1) - 30(k - 6)]/(5(k - 6)(k + 1))#

so, #[3k^2 + 3k - 30k + 180]/(5(k - 6)(k + 1))#

=> #(3k^2 - 27k + 180)/(5(k - 6)(k + 1))#