How do you solve #4n ^ { 2} - 8n = 0#?

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Answer 1 · 2017-05-17T18:49:54

Rearranging this, we get :

#n(4n-8)=0#

So basically :

#n = 0# or #4n-8 = 0#

Thus, the final answer would be:

#n = 0# or #n = 2#

Answer 2 · 2017-05-17T18:53:59

#n=0" "or" "n=2#

#4n^2-8n=0#
#" "#
#rArr4n(n-2)=0#
#" "#
#rArr4n=0rArrn=0#
#Or#
#rArrn-2=0rArrn=2#
#" "#
The solutions are either #n=0" "or" "n=2#