Question #1cdc2

1 Answer
Astralboy
May 17, 2017

#.539#

Explanation:

We know that there's a set number of trials: #5#

We also know that the chances of getting an integer less than #4# is #3/9#.

Since we want at least #2#, that means we want #2# or more. Unfortunately, #bcdf# will find #2# or less if we put in #2#. Instead, we want to do #1-bcdf(1)#.

#1-bcdf(5,3/9,2)=.539#

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