Question

Question #eee3a

Answer 1

The substance is most likely iron.

Explanation:

It looks as if we should calculate the specific heat capacity of the substance.

The formula for the amount heat `q` absorbed by a substance is

`color(blue)(bar(ul(|color(white)(a/a)q = mCΔTcolor(white)(a/a)|)))" "`

where

`m` is the mass of the substance
`C` is the specific heat capacity of the material
`ΔT` is the temperature change

You can rearrange the formula to calculate the specific heat capacity:

`C = q/(mΔT)`

In this problem,

`q = 1.539 × 10^2color(white)(l) "J"`
`m = "17.1 g"`
`ΔT = "(45.0 - 25.0) °C" = "20.0 °C"`

∴ `C = (1.539 × 10^2color(white)(l) "J")/"17.1 g × 20.0 °C" = "0.450 J·°C"^"-1""g"^"-1"`

The Engineering Toolbox lists the following specific heat capacities of metals:

`"Cr = 0.46 kJ/(K·kg)"`
`"Fe = 0.45 kJ/(K·kg)"`
`"Ni = 0.44 kJ/(K·kg)"`

I will go for the one in the middle and say that the substance is most likely iron.