Question

Calculate the percentage yield of ferrous sulfide if 3 moles of iron produces 220 grams of ferrous sulfide?

Answer 1

First we calculate the theoretic yield.

Explanation:

3 mol of `Fe` should yield 3 mol `FeS`

`m(FeS)=m(Fe)+m(S)=55.85+32.07=87.92`

3 mol should have a mass of `3xx87.92=263.76`

So percent yield is `220/263.76=0.834~~83%`