How do you solve #13x ^ { 2} - 18x = 0#?

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Answer 1 · 2017-05-18T19:01:07

#x=0,18/13#

Factor out an #x#:

#x(13x-18)=0#

Now solve for each of the factors:

#x=0#

#13x-18=0#

#x=18/13#

So the two zeroes are:

#x=0,18/13#